-15x^2+32x+60=0

Solution for -15x^2+32x+60=0 equation:

-15x^2+32x+60=0

a = -15; b = 32; c = +60;
Δ = b2-4ac
Δ = 322-4·(-15)·60
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-68}{2*-15}=\frac{-100}{-30}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+68}{2*-15}=\frac{36}{-30}
=-1+1/5
$